树莓派驱动8*8LED点阵

二进制病毒

     这里只是为了练习GPIO的使用，没有加任何的译码设备，也没加任何的放大设备，直接用树莓派的16个gpio引脚，连接一个8*8LED点阵的16个引脚，考虑到树莓派所能提供的电流不能太大，所以统一在点阵的8个阳极各加了一个1kΩ的电阻
    8*8电阻的16个引脚，8个阳极，8个阴极，我们可以第一为R1~R8、C1~C8（考虑到点阵是方形的，所以不去区分行列，只区分阴阳，上面的R/C和“阴/阳”的对应关系，请根据实际共阴还是共阳区分清楚）
    下面几段核心的python代码
    管脚对应关系，这里和gpio与8*8点阵的链接有关

1. rs = [21, 20, 16, 12, 25, 24, 23, 18] #R1:13 R2:3 R3:4 R4:10 R5:6 R6:11 R7:15 R8:16
   
2. cs = [26, 19, 13, 6, 5, 22, 27, 17] #C1:5 C2:2 C3:7 C4:1 C5:12 C6:8 C7:14 C8:9

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字模，八行，N列

1. #Hello World
   
2. vhws = [
   
3.   [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
   
4.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,1,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0],
   
5.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,1,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0],
   
6.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,0,1,0,0,0,1,1,0,1,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0],
   
7.   [0,0,0,0,0,0,0,0,1,1,1,1,1,0,1,1,1,1,1,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0,1,1,1,0,0,0,0,0,0],
   
8.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,0,0],
   
9.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,0,1,0,1,0,0,1,0,0,1,0,0,0,0,0,0],
   
10.   [0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,1,1,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,1,1,1,1,0,0,0,0,0],
    
11. ]

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从字模里拿一个8*8数组

1. isRig = 1
   
2. vhwi = 0
   
3. def hwv():
   
4.   global isRig
   
5.   global vhwi
   
6.   l = len(vhws[0])
   
7.   if isRig > 0:
   
8.     vhwi += 1
   
9.   else:
   
10.     vhwi -= 1
    
11.   if vhwi >= (l - 8):
    
12.     isRig = 0
    
13.   if vhwi <= 0:
    
14.     isRig = 1  
    
15.   r = []
    
16.   for i in range(0, len(vhws)):
    
17.     j = vhwi

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详细的代码请看我的博客：http://www.jiangkunlun.com/2015/04/led_8/